Consider the following loop LOOP LDUR X10 X1 0 LDUR X11 X1 8 ADD X12 X10 X11 SUBI X 1 X 1 16 CBNZ X12 LOOP Question 4251 Show a pipeline execution diagram for the first two iterations of this loop llllllllllllllll Cycle 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Loop(x) 1 LDUR X10 X1 0 IF ID EX MEM WB LDUR X11 X1 8 IF ID EX MEM WB ADD X12 X10 X11 IF ID EX MEM WB SUBI X1 X1 16 IF ID EX MEM WB CBNZ X12 LOOP IF ID EX MEM WB 2 LDUR X10 X1 0 IF ID EX MEM WB LDUR X11 X1 8 IF ID EX MEM WB ADD X12 X10 X11 IF ID EX MEM WB SUBI X1 X1 16 IF ID EX MEM WB CBNZ X12 LOOP IF ID EX MEM WB Question 4252 Mark pipeline stages that do not perform useful work How often while the pipeline is full do we have a cycle in which all five pipeline stages are doing useful work (Begin with the cycle during which the SUBI is in the IF stage End with the cycle during which the CBNZ is in the IF stage)

Question

Consider the following loop LOOP LDUR X10 X1 0 LDUR X11 X1 8 ADD X12 X10 X11 SUBI X 1 X 1 16 CBNZ X12 LOOP Question 4251 Show a pipeline execution diagram for the first two iterations of this loop llllllllllllllll  Cycle 1 2 3 4 5 6 7 8 9 10 11 12 13 14  Loop(x)         1 LDUR X10 X1 0 IF ID EX MEM WB       LDUR X11 X1 8  IF ID EX MEM WB      ADD X12 X10 X11  IF ID EX MEM WB      SUBI X1 X1 16   IF ID EX MEM WB     CBNZ X12 LOOP   IF ID EX MEM WB    2 LDUR X10 X1 0    IF ID EX MEM WB    LDUR X11 X1 8    IF ID EX MEM WB    ADD X12 X10 X11     IF ID EX MEM WB   SUBI X1 X1 16     IF ID EX MEM WB   CBNZ X12 LOOP      IF ID EX MEM WB  Question 4252 Mark pipeline stages that do not perform useful work How often while the pipeline is full do we have a cycle in which all five pipeline stages are doing useful work (Begin with the cycle during which the SUBI is in the IF stage End with the cycle during which the CBNZ is in the IF stage)

StudyX AI Fast Model · Accepted Answer

Solution By Steps
Step 1: LDUR X10, [X1, \#0]
In Cycle 1: Instruction Fetch (IF)
In Cycle 2: Instruction Decode (ID)
In Cycle 3: Execute (EX)
In Cycle 4: Memory Access (MEM)
In Cycle 5: Write Back (WB)

Step 2: LDUR X11, [X1, \#8]
In Cycle 2: IF
In Cycle 3: ID
In Cycle 4: EX
In Cycle 5: MEM
In Cycle 6: WB

Step 3: ADD X12, X10, X11
In Cycle 4: IF
In Cycle 5: ID
In Cycle 6: EX
In Cycle 7: MEM
In Cycle 8: WB

Step 4: SUBI X1, X1, \#16
In Cycle 6: IF
In Cycle 7: ID
In Cycle 8: EX
In Cycle 9: MEM
In Cycle 10: WB

Step 5: CBNZ X12, LOOP
In Cycle 8: IF
In Cycle 9: ID
In Cycle 10: EX
In Cycle 11: MEM
In Cycle 12: WB

Step 6: Repeat Steps 1-5 for the second iteration

Final Answer
Useful work stages: EX, MEM, WB
Non-useful work stages: IF, ID

Key Concept
Pipeline Efficiency

Key Concept Explanation
In a pipeline, the efficiency is maximized when all stages are performing useful work. Identifying and minimizing non-useful stages like IF and ID can enhance the overall throughput of the pipeline, reducing idle cycles and improving performance.

Consider the following loop LOOP LDUR X10 X1 0 LDUR X11 X1 8 ADD X12 X10 X11 SUBI X 1 X 1 16 CBNZ X12 LOOP Question 4251 Show a pipeline execution diagram for the first two iterations of this loop...

Question

Answer & Explanation

Follow-up Knowledge or Question

Learn More

Consider the following loop LOOP LDUR X10 X1 0 LDUR X11 X1 8 ADD X12 X10 X11 SUBI X 1 X 1 16 CBNZ X12 LOOP Question 4251 Show a pipeline execution diagram for the first two iterations of this loop...

Question

Answer & Explanation

Follow-up Knowledge or Question

Questions asked by other users